Give the product from the following reaction | vedclass

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(D) The starting material is $3$-(hydroxymethyl)cyclopentan-$1$-one. $1$. The reaction with ethylene glycol in the presence of $H^+$ forms a cyclic ac

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$3-$($1$-hydroxypropyl)cyclopentan$-1-$one

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(D) The starting material is $3$-(hydroxymethyl)cyclopentan-$1$-one. $1$. The reaction with ethylene glycol in the presence of $H^+$ forms a cyclic acetal (protecting group) at the ketone position,yielding $3$-(hydroxymethyl)cyclopentan-$1$-one ethylene acetal. $2$. Treatment with $PCC$ (Pyridinium chlorochromate) oxidizes the primary alcohol group $(-CH_2OH)$ to an aldehyde group $(-CHO)$,resulting in $3$-oxocyclopentane-$1$-carbaldehyde ethylene acetal. $3$. Addition of $EtMgBr$ (Grignard reagent) followed by $H_3O^+$ workup attacks the aldehyde carbonyl,converting it into a secondary alcohol,and simultaneously deprotects the cyclic acetal back to the ketone. $4$. The final product is $3$-($1$-hydroxypropyl)cyclopentan-$1$-one.

Give the product from the following reaction sequence:

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